Answer: 0.123 M
Explanation:
According to the neutralization law:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of [tex]HBr[/tex] solution = ?
[tex]V_1[/tex] = volume of [tex]HBr[/tex] solution = 15.00 ml
[tex]M_2[/tex] = molarity of [tex]KOH[/tex] solution = 0.100 M
[tex]V_2[/tex] = volume of [tex]KOH[/tex] solution = 18.44 ml
[tex]n_1[/tex] = valency of [tex]HBr[/tex] = 1
[tex]n_2[/tex] = valency of [tex]KOH[/tex] = 1
[tex]1\times M_1\times 15.00=1\times 0.100\times 18.44[/tex]
[tex]M_1=0.123[/tex]
Therefore, the concentration of the unknown HBr solution is 0.123 M