Answer:
The current through the block is 40.8mA
Explanation:
For question a we can apply the macroscopic form of Ohm's law:
[tex]I=\frac{V}{R}[/tex]
where:
V= potential difference
R= The resistance of the block
substituting the values on the formula we have:
[tex]I=\frac{39.9V}{977 \Omega}\\\\I=40.8mA[/tex]