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Funtime Amusement Park charges $12.50 for administration and then $0.75 per ride. River’s Edge Park charges $18.50 for admission and then $0.50 per ride. For what number of rides is the cost the same at both parks?

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Both parks will have the same cost for 24 rides

Step-by-step explanation:

The question requires linear equation to be solved.

Let a be the admission fee and r be the number of rides

Then

For Funtime PArk the expression will be:

Admission Charges =a = $12.50

Ride charges = r = $0.75

12.50+0.75r

For River's Edge Park the expression will be:

Admission Charges =a = $18.50

Ride charges = r = $0.50

18.50+0.50r

Putting both expressions equal:

[tex]12.50+0.75r=18.50+0.50r\\Subtracting\ 0.50\ from\ both\ sides\\12.50+0.75r-0.50r=18.50+0.50r-0.50r\\12.50+0.25r=18.50\\Subtracting\ 12.50\ from\ both\ sides\\12.50+0.25r-12.50=18.50-12.50\\0.25r=6\\Dividing\ both\ sides\ by\ 0.25\\\frac{0.25r}{0.25}=\frac{6}{0.25}\\r=24[/tex]

Both parks will have the same cost for 24 rides

Keywords: Linear Equations

Learn more about linear equations at:

  • brainly.com/question/7265276
  • brainly.com/question/7294502

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The number of rides when both parks would cost the same is 24.

What is the number of rides when the costs at both parks would be the same?

The equation that represents the cost at Funtime Amusement Park is: $12.50 + $0.75a

The equation that represents the cost at River’s Edge Park is: $18.50 + $0.50a

Where a represents cost per ride.

At the point where the cost would be the same, the equations would be equal. $12.50 + $0.75a =  $18.50 + $0.50a

$18.50 - $12.50 = 0.75a - 0.50a

$6 = 0.25a

a = 24

To learn more about cost, please check: https://brainly.com/question/25717996

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