Answer:
12m
Step-by-step explanation:
Given: [tex]$ \frac{\frac{16m^2}{m^2 + 5}}{{\frac{4m}{3m^2 + 15}}} $[/tex]
This is nothing but
[tex]$ \frac{16m^2}{m^2 + 5} \times \frac{4m}{3m^2 + 15} $ because we have $\frac {\frac{a}{b} } { \frac{c}{d} } = \frac{a}{b} \times \frac{d}{c} $[/tex]
Now, this becomes [tex]$ \frac{16m^2}{m^2 + 5} \times \frac{3(m^2 + 5)}{4m} $[/tex].
Cancelling the common terms, we get [tex]$ 3 (4m) = 12m $[/tex].
Hence the answer
