Answer:
The magnitude of the resulting torque [tex]=118 N.m[/tex]
Explanation:
The resulting torque = Force [tex]\times[/tex] perpendicular distance.
So the force [tex]=mass\times gravity =10\times 9.8 =98\ N[/tex]
Perpendicular distance [tex]= 1.2\ m[/tex]
Torque = [tex]F \times d = 98\times 1.2 = 117 .6 N\ m \approx 118 N\ m[/tex]
The direction will be clockwise as the force acting is downward and will pull the rod in clockwise direction.
So the torque is [tex]118\ N\ m[/tex] in cw(clockwise) direction.
