An atom's outermost electron arrangement determines how it interacts with other atoms. Which of the following atomic structures would be most likely to form an ionic bond? A. neon, which has eight outer electrons B. carbon, which has four outer electrons C. helium, which has two outer electrons D. fluorine, which has seven outer electrons

Respuesta :

Answer: d fluorine

Explanation:

The element that could interact to form an ionic bond is fluorine, which has seven outer electrons.

What is electron arrangement?

The term electron arrangement has to do with how the electrons are positioned in the orbits or shells of an atom. The atoms that are metals have fewer outermost electrons while non metals have a greater number of outermost electrons.

The element that could interact to form an ionic bond is fluorine, which has seven outer electrons.

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