Answer:
The desired such number is 3.
Step-by-step explanation:
Let the given such number = m
Now, 42 is divided by m ⇒[tex]\frac{42}{m}[/tex] is the desired expression.
Now, The quotient is added to 11.
⇒[tex]\frac{42}{m} + 11[/tex] is the desired expression.
The sum is again multiplied by 5.
⇒[tex](\frac{42}{m} + 11) \times 5[/tex] is the desired expression.
The product is 125.
⇒[tex](\frac{42}{m} + 11) \times 5 = 125[/tex] is the desired expression.
Now, solving for the value of m , we get:
[tex](\frac{42}{m} + 11) \times 5 = 125 \implies(\frac{42}{m} + 11) = \frac{125}{5} \\or, (\frac{42}{m} + 11) = 25\\or, (\frac{42}{m} ) = 25 - 11 = 14[/tex]
⇒[tex]\frac{42}{m} = 14 \implies m = \frac{42}{14} = 3[/tex]
or, m = 3
Hence, the desired such number is 3.
