Answer:
Y = 6x + 43 is the line that passes through point (-7, 1).
Step-by-step explanation:
Given line = Y = 6x + 1
From the slope intercept form y = mx + c; m= 6
For a parallel line, slopes must be equal i.e. m = 6
Now, for (-7, 1) and m = 6 we know that point slope form is [tex]\mathrm{Y}-\mathrm{Y}_{1}=\mathrm{m}\left(\mathrm{X}-\mathrm{X}_{1}\right)[/tex]
Line = Y – 1 = 6 (x-(-7)) [tex]\Rightarrow[/tex] Y-1= 6(x+7) [tex]\Rightarrow[/tex] Y-1 = 6x+42 [tex]\Rightarrow[/tex] Y = 6x + 43 Hence, the line is y = 6x + 43