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A catcher catches a 145 g baseball traveling horizontally at 32.0 m/s. Part APart complete How large an impulse does the ball give to the catcher? Express your answer in kilogram-meters per second. pp = 4.64 kg⋅m/s SubmitPrevious Answers Correct Part B If it takes the ball 20 s to stop once it is in contact with the catcher's glove, what average force did the ball exert on the catcher? Express your answer in newtons.

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To solve this problem we need the concepts related to Energy in terms of momentum and the average force of a body given by Newton's second law.

Energy in terms of momentum is given by the equation

[tex]J =mv[/tex]

Where,

m=mass

v=velocity

Part A) For the first part we understand that the impulse would be,[tex]J = (0.145)(32)\\J = 4.64 kg*m/s[/tex]

Part B) For part B the average force is given by,

[tex]F= ma[/tex]

Where,

m = mass

a = acceleration, which is also given by [tex]a=\frac{v}{t}[/tex]

Then,

[tex]F=m\frac{v}{t}[/tex]

[tex]F= 0.145*\frac{32}{20}[/tex]

[tex]F= 0.232N[/tex]

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