The angle above the horizontal of a baseball thrown with an initial velocity of 14 m/s is 44.43° if it remained in air for 2 seconds.
Explanation:
To find: angle Ф of launch above horizontal
A projectile motion is a form of motion where an object thrown at some angle with some initial velocity travels in a symmetrical parabolic path. Projectile motion only occurs when there is one force applied at the beginning on the trajectory, after which the only interference is from gravity.
Time of Flight:
The time of flight of a projectile motion is the time from when the object is projected to the time it reaches the surface. Time of flight of an object moving in a parabolic motion depends on the initial velocity magnitude and the angle of the projectile.
The formula for time of flight is given as:
T = 2 v*sinФ/g
Here T is the time of flight. Ф is the angle. v is is initial velocity and g = 9.8 m/s².
We know the value of other terms and we can find the angle Ф using the formula given above.
T = 2 v*sinФ/g
v*sinФ = T*g/2
sinФ = T*g/2v
sinФ = 2*9.8/2*14
sinФ = 0.7
Taking sin inverse on both sides:
Ф = sin⁻¹(0.7)
Ф = 44.43°
Learn more about projectile motion from https://brainly.com/question/12613293
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