Dad is 4 times as old as his son Jim. In 10 years, Dad's age will be 20 years more than twice Jim's age. How old is Jim?

If D = dad's age now and J = Jim's age now, which of the following systems could be used to solve the problem?

a. D = 4J and D + 10 = 2J + 20
b. D = 4J and D + 10 = 2(4J + 10) + 20
c. D = 4J and D + 10 = 2(J + 10) + 20

Respuesta :

Let's focus on the "In 10 years" part

in 10 years
D will be (D + 10)
and J will be (J + 10)

"twice Jim's age" would then be 2(J + 10)
and
"20 years more than" that would be 2(J + 10) + 20

so
the answer with
D + 10 = 2(J + 10) + 20
would be your answer
that is, C.

Answer: The correct answer would be C:

Step-by-step explanation:

D=4J and D+10=2(J+10)+20