Answer:
There are two real, distinct roots to the quadratic equation .
Step-by-step explanation:
Given : -2x² + 3 = 0.
To find : Determine the discriminant and how many real number solutions does the equation have.
Solution : We have given -2x² + 3 = 0.
On comparing ax²+bx +c = 0
Discriminant = b² - 4ac
Where b = -2 , c = 3
Plugging the values
D = ( -2)² - 4 ( -2) ( 3) .
D = 4 + 24 .
D = 28 > 0
If the discriminant is greater than zero, this means that the quadratic equation has two real, distinct (different) roots.
Therefore, There are two real, distinct roots to the quadratic equation .
