Respuesta :
Hello,
Answer A
Let's the width of the rectangle
2a-5 its length
Teh half perimeter is 80/2=40
a+2a-5=40 ==>3a=45==>a=15 and 2a-5=30-5=25
Answer A
Let's the width of the rectangle
2a-5 its length
Teh half perimeter is 80/2=40
a+2a-5=40 ==>3a=45==>a=15 and 2a-5=30-5=25
Answer:
Length = 25 cm , Width = 15 cm.
Step-by-step explanation:
Given : The length of a rectangle is 5 centimeters less than twice its width. The perimeter of the rectangle is 80 cm.
To find : What are the dimensions of the rectangle.
Solution : We have given
Perimeter = 80 cm .
According to question :
Let width of rectangle = W .
Length is twice its width.
L = 2W .
Length of a rectangle is 5 centimeters less than twice its width.
L = 2W - 5.
Then ,
Perimeter = 2 ( length + width).
Plug the values
80 = 2 ( 2W - 5 + W ) .
80 = 2( 3W -5) .
On dividing both sides by 2
40 = 3W - 5 .
On adding both sides by 5.
45 = 3 W .
On dividing both sides by 3.
W = 15 cm .
L = 2W - 5.
L = 2 ( 15) - 5 .
L = 30 -5 .
L = 25 cm .
Therefore, Length = 25 cm , Width = 15 cm.