Specific gravity is defined as the ratio of the density of a substance to the density of reference substance. In this case the reference substance is water. Given that the density of water at 4.00 C is 1.00 g/cm3, then density of iron is 7.87 g/cm3.
Given 4.50 g iron (cm3 iron/ 7.87 g iron) = 0.571 cm3
Answer: The volume of iron occupied is [tex]0.572cm^3[/tex]
Explanation:
The relationship between specific gravity and density of a substance is given as:
[tex]\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}[/tex]
Specific gravity of iron = 7.87
Density of water = [tex]1.00g/cm^3[/tex]
Putting values in above equation we get:
[tex]7.87=\frac{\text{Density of iron}}{1.00g/cm^3}\\\\\text{Density of iron}=7.87g/cm^3[/tex]
To calculate volume of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of iron = [tex]7.87g/cm^3[/tex]
Mass of iron = 4.50 g
Putting values in above equation, we get:
[tex]7.87g/cm^3=\frac{4.50g}{\text{Volume of iron}}\\\\\text{Volume of iron}=0.572cm^3[/tex]
Hence, the volume of iron occupied is [tex]0.572cm^3[/tex]
