A raindrop has a mass of 50. mg and the Pacific Ocean has a mass of 7.08 X 10^20 kg. Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of raindrops? Round your answer to 2 significant digits. How many moles of raindrops are in the Pacific Ocean? Round your answer to 2 significant digits.

Respuesta :

Explanation:

It is known that according to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms.

Therefore, mass of 1 mole of raindrops is as follows.

    Mass of 1 mole raindrops = mass of 1 rain drop × Avogadro's number

                       = [tex]50 \times 6.022 \times 10^{23}[/tex]

                       = [tex]301.1 \times 10^{23}[/tex] mg

or,                   = [tex]3.0 \times 10^{22}[/tex]          (as 1 mg = 0.001 g)

Therefore, mass of 1 mole of raindrops is [tex]3.0 \times 10^{22}[/tex] g.

Now, the mass of Pacific ocean is calculated as follows.

            Mass of Pacific ocean = [tex]\frac{\text{mass of pacific ocean}}{\text{mass of 1 mole of raindrops}}[/tex]

As 1 kg = 1000 g. So, mass of Pacific ocean will be [tex]7.08 \times 10^{20} kg[/tex] equal to [tex]7.08 \times 10^{23} g[/tex].

Hence, moles of raindrops will be calculated as follows.

          Mass of Pacific ocean = [tex]\frac{\text{mass of pacific ocean}}{\text{mass of 1 mole of raindrops}}[/tex]

                          = [tex]\frac{7.08 \times 10^{23}}{3.0 \times 10^{22}}[/tex]

                          = 24 moles

Therefore, we can conclude that 24 moles of raindrops are in the Pacific Ocean.