Explanation:
It is known that according to mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms.
Therefore, mass of 1 mole of raindrops is as follows.
Mass of 1 mole raindrops = mass of 1 rain drop × Avogadro's number
= [tex]50 \times 6.022 \times 10^{23}[/tex]
= [tex]301.1 \times 10^{23}[/tex] mg
or, = [tex]3.0 \times 10^{22}[/tex] (as 1 mg = 0.001 g)
Therefore, mass of 1 mole of raindrops is [tex]3.0 \times 10^{22}[/tex] g.
Now, the mass of Pacific ocean is calculated as follows.
Mass of Pacific ocean = [tex]\frac{\text{mass of pacific ocean}}{\text{mass of 1 mole of raindrops}}[/tex]
As 1 kg = 1000 g. So, mass of Pacific ocean will be [tex]7.08 \times 10^{20} kg[/tex] equal to [tex]7.08 \times 10^{23} g[/tex].
Hence, moles of raindrops will be calculated as follows.
Mass of Pacific ocean = [tex]\frac{\text{mass of pacific ocean}}{\text{mass of 1 mole of raindrops}}[/tex]
= [tex]\frac{7.08 \times 10^{23}}{3.0 \times 10^{22}}[/tex]
= 24 moles
Therefore, we can conclude that 24 moles of raindrops are in the Pacific Ocean.