Respuesta :
Answer:
The thermal efficiency of the power cycle is 5 %.
Explanation:
Given that,
Surface temperature = 25°C
Under water temperature = 80°C
Output power = 12 kW
Rate = 14400 kJ/min = 240 kJ/sec
Suppose we need to find the thermal efficiency of the power cycle
We need to calculate the thermal efficiency
Using formula of the thermal efficiency
[tex]\eta=\dfrac{W}{Q_{1}}[/tex]
Where, Q₁ = heat input
We know that,
[tex]W=Q_{1}-Q_{2}[/tex]
[tex]Q_{1}=W+Q_{2}[/tex]
[tex]Q_{1}=10+240[/tex]
Now put the value of Q and W in to the formula of efficiency
[tex]\eta=\dfrac{12}{240}[/tex]
[tex]\eta=0.05[/tex]
[tex]\eta=5\%[/tex]
Hence, The thermal efficiency of the power cycle is 5 %.
Answer:
4.76%
Explanation:
The thermal efficiency of the cycle can be determined by using the formula
η = W / Qin. W is the work, and is equal to Qin - Qout.
Rearranging for Qin: Qin = W + Qout
Plugging in the given numbers: Qin = 12 + (14400/60) = 12 + 240 = 252
Plugging this value into the first equation: η = 12/252 = 0.0476
The thermal efficiency is 4.76%.