Respuesta :
Answer:
In order to cancel the electrons,. the oxidation half reaction must be multiplied by 4 and the reduction half reaction must be multiplied by 3.
Explanation:
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
[tex]X\rightarrow X^{n+}+ne^-[/tex]
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
[tex]X^{n+}+ne^-\rightarrow X[/tex]
The half cell reactions for the above reaction follows:
Oxidation half reaction: [tex]A_{2}^+\rightarrow 2A^{2+}+3e^-[/tex]
Reduction half reaction: [tex]B+4e^-\rightarrow B^{4-}[/tex]
Thus, in order to cancel the electrons,. the oxidation half reaction must be multiplied by 4 and the reduction half reaction must be multiplied by 3.
Thus,
4*Oxidation half reaction: [tex]4A_{2}^+\rightarrow 8A^{2+}+12e^-[/tex]
3*Reduction half reaction: [tex]3B+12e^-\rightarrow 3B^{4-}[/tex]
Overall reaction:-
[tex]4A_{2}^++3B\rightarrow 8A^{2+}+3B^{4-}[/tex]
