Respuesta :
Answer:
a) Mass of solution is 16,605 milli grams.
b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
Explanation:
Mass by mass percentage of calcium chloride solution, wt% = 12.0%
Density of the solution = d = 1.107 g/mL
a) Volume of the solution , V= 15.0 mL
Mass of the solution = m
[tex]Mass=density\times Volume[/tex]
[tex]m=d\times V=1.107 g/ml\times 15.0 mL=16.605 g[/tex]
Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)
b) Mass of the solution = m
Volume of the solution = V = 431.3 mL
[tex]Mass=density\times Volume[/tex]
[tex]m=d\times V=1.107 g/ml\times 431.3 mL=477.4491 g[/tex]
Mass of calcium chloride = x
w% = 12.0%
[tex]\frac{x}{M}\times 100=12\%[/tex]
[tex]x=12\times \frac{M}{100}=12\times \frac{477.4491 g}{100}=57.29 g[/tex]
57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.
c) Moles of calcium chloride = [tex]\frac{57.99 g}{111 g/mol}=0.5161 mol[/tex]
[tex]Molarity(M)=\frac{moles(n)}{V(L)}[/tex]
V = Volume of the solution in Liters
n = 0.5161 mole
V = 431.3 mL = 0.4313 L
[tex]M=\frac{0.5161 mol}{0.4313 L}=1.1967 mol/L[/tex]
1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.
