Answer:
The diameter of the circle O is 12 units
Step-by-step explanation:
There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of
[tex]BC=6\sqrt{2}[/tex]
and the triangle B0C is right
Relations in the Circle
The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.
Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r
Applying Pythagoras's theorem:
[tex]BC^2=r^2+r^2=2r^2[/tex]
Thus we have
[tex]2r^2=(6\sqrt{2})^2[/tex]
[tex]2r^2=72[/tex]
[tex]r^2=36[/tex]
[tex]r=6[/tex]
The diameter of the circle O is D=2(6) = 12 units
