Answer:
Part A). The intersection point of the line is (-2,1)
Part B). The intersection points of the line line itself
Step-by-step explanation:
The equation of a line is given by y=mx+c
Where, m= slope and c=y-intercept.
Part A).
Given two-equation of a line is :
1. y=x+3
2. y=(-2)x-3
To plot graph:
We need at least two points to plot the line.
For a line: y=x+3
When x=0
y=x+3
y=0+3=3
When x=1
y=x+3
y=1+3=4
Point (0,3) and (1,4) is on line y=x+3,
For a line: y=(-2)x-3
When x=0
y=(-2)x-3
y=0+3=(-3)
When x=1
y=(-2)x-3
y=(-2)1-3=(-5)
Point (0,-3) and (1,-5) is on line y=(-2)x-3
Thus, From the graph, The intersection point of the line is (-2,1)
Part B).
Given two equation of a line is :
1. y-6=2x
2. y=2(x+1)+4=2x+2+4=2x+6
To plot graph:
We need at least two points to plot the line.
For a line: y-6=2x
When x=0
y-6=2x
y-6=0
y=6
When x=1
y-6=2x
y-6=2(1)
y=8
Point (0,6) and (1,8) is on line y-6=2x
For a line: y=2x+6
When x=0
y=2x+6
y=0+6=6
When x=1
y=2x+6
y=(2)+6=8
Point (0,6) and (1,8) is on line y=2x+6
Thus,
From the graph, Both the line are same, the intersection points of the line line itself
