Answer:
Explanation:
The ant , at some point of time will be standing on the crest of moving wave passing under its feet . At that position the downward acceleration of the ant will be equal to its weight . Hence it will feel weightlessness . So at that time
Acceleration = g
Acceleration at the top position = ω²A where ω is angular velocity and A is amplitude of vibration ( transverse ) of crest .
ω =2 π n where n is frequency of transverse vibration of particles. This angular frequency will be equal to angular frequency of wave travelling on the rope .
frequency of travelling wave
n.= [tex]\frac{1}{\gamma}\sqrt{\frac{T}{\mu} }[/tex]
ω =2 π x [tex]\frac{1}{\gamma}\sqrt{\frac{T}{\mu}[/tex]
ω² = 4π² x T/γ²μ}
For weightlessness
ω² A = g
A= g x γ²μ / 4π² T