Respuesta :
Answer:
The final temperature of the water is 22.44°C.
Explanation:
Heat lost by tin will be equal to heat gained by the water
[tex]-q_1=q_2[/tex]
Mass of tin = [tex]m_1=18.5 g[/tex]
Specific heat capacity of tin = [tex]c_1=0.21 J/g^oC [/tex]
Initial temperature of the tin = [tex]T_1=97.38^oC[/tex]
Final temperature = [tex]T_2[/tex]=T
[tex]q_1=m_1c_1\times (T-T_1)[/tex]
Mass of water= [tex]m_2=75.7 g[/tex]
Specific heat capacity of water= [tex]c_2=4.184 J/g^oC [/tex]
Initial temperature of the water = [tex]T_3=21.52^oC[/tex]
Final temperature of water = [tex]T_2[/tex]=T
[tex]q_2=m_2c_2\times (T-T_3)[/tex]
[tex]-q_1=q_2[/tex] (Law of Conservation of energy)
[tex]-(m_1\times c_1\times (T-T_1))=m_2\times c_2\times (T-T_3)[/tex]
On substituting all values:
[tex]-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)[/tex]
we get, T = 22.44°C
The final temperature of the water is 22.44°C.
