Answer:
12 A
Explanation:
[tex]N_p[/tex] = Number of turns in the primary coil = 500
[tex]N_s[/tex] = Number of turns in the secondary coil = 2000
[tex]I_p[/tex] = Current in the primary coil
[tex]I_s[/tex] = Current in the secondary coil = 3 A
Transformers follow the equation
[tex]\frac{N_p}{N_s}=\frac{I_s}{I_p}\\\Rightarrow I_p=\frac{I_s\times N_s}{N_p}\\\Rightarrow I_p=\frac{3\times 2000}{500}\\\Rightarrow I_p=12\ A[/tex]
The current in the primary coil is 12 A
An ideal transformer follows the above equation
