A system of ideal gas at 22°C undergoes an ischoric process with an internal energy decrease of 4.30 × 10 3 4.30×103 J to a final temperature of 16°C. What is the approximate change in entropy?[Hint: use the average temperature]

Respuesta :

Answer:

The approximate change in entropy is -14.72 J/K.

Explanation:

Given that,

Temperature = 22°C

Internal energy [tex]U=4.30\times10^{3}\ J[/tex]

Final temperature = 16°C

We need to calculate the approximate change in entropy

Using formula of the entropy

[tex]\Delta S=\dfrac{\Delta U}{T}[/tex]

Where, [tex]\Delta U[/tex] = internal energy

T = average temperature

Put the value in to the formula

[tex]\Delta S=\dfrac{-4.30\times10^{3}}{\dfrac{22+273+16+273}{2}}[/tex]

[tex]\Delta S=-14.72\ J/K[/tex]

Hence, The approximate change in entropy is -14.72 J/K.