Answer:
x = 1 , y = 0
Step-by-step explanation:
Solve the following system:
{y = 2 x - 2 | (equation 1)
y = x - 1 | (equation 2)
Express the system in standard form:
{-(2 x) + y = -2 | (equation 1)
-x + y = -1 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{-(2 x) + y = -2 | (equation 1)
0 x+y/2 = 0 | (equation 2)
Multiply equation 2 by 2:
{-(2 x) + y = -2 | (equation 1)
0 x+y = 0 | (equation 2)
Subtract equation 2 from equation 1:
{-(2 x)+0 y = -2 | (equation 1)
0 x+y = 0 | (equation 2)
Divide equation 1 by -2:
{x+0 y = 1 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = 1 , y = 0
The solution of given linear system of the equations is given by:
(x,y) = (1,0)
[tex]y = 2x - 2\\y = x - 1[/tex]
Putting value of y from first equation in second equation, we get:
[tex]2x - 2 = x - 1\\2x -x = 2 - 1\\x = 1[/tex]
The value of y will be:
[tex]y = x - 1 = 1 -1 = 0[/tex]
Thus, the solution of the given system of linear equations is (x,y) = (1,0)
The solution of these equations can be found on the graph where these lines intersect. See the graph given below.
Learn more about linear equations here:
https://brainly.com/question/14491895
