Answer:
a) x is the number of shots that he makes.
[tex]P(X = 0) = 0.55[/tex]
[tex]P(X = 1) = 0.25[/tex]
[tex]P(X = 0) = 0.20[/tex]
b) There is an 80% probability that he makes no more than one of the shots.
c) There is a 45% probability that he makes at least one of the shots.
Step-by-step explanation:
In this problem, we have these following probabilities:
A 55% probability that the player miss both shoots.
A 25% that he makes one shot.
A 20% probability that he makes both shots.
a. Construct the appropriate probability distribution.
I am going to say that x is the number of shots that he makes. So:
[tex]P(X = 0) = 0.55[/tex]
[tex]P(X = 1) = 0.25[/tex]
[tex]P(X = 0) = 0.20[/tex].
b. What is the probability that he makes no more than one of the shots?
[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.55 + 0.25 = 0.80[/tex]
There is an 80% probability that he makes no more than one of the shots.
c. What is the probability that he makes at least one of the shots?
[tex]P(X \geq 1) = P(X = 1) + P(X = 2) = 0.25 + 0.20 = 0.45[/tex]
There is a 45% probability that he makes at least one of the shots.