Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion? A. 0.10 M Al3+ ions and 0.30 M Br- ions B. 0.30 M Al3+ ions and 0.10 M Br- ions C. 0.10 M Al3+ ions and 0.033 M Br- ions D. 0.033 M Al3+ ions and 0.033 M Br- ions

Respuesta :

Answer: The concentration of [tex]Al^{3+}[/tex] ions is 0.10 M and that of [tex]Br^-[/tex] ions is 0.30 M

Explanation:

We are given:

Concentration of [tex]AlBr_3[/tex] = 0.10 M

The chemical equation for the ionization of aluminium bromide follows:

[tex]AlBr_3\rightarrow Al^{3+}+3Br^-[/tex]

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions

So, concentration of aluminium ions = 0.10 M

Concentration of bromide ions = [tex][(3\times 0.1)]=0.3M[/tex]

Hence, the concentration of [tex]Al^{3+}[/tex] ions is 0.10 M and that of [tex]Br^-[/tex] ions is 0.30 M

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