Answer:
28.05% is the mass percent of calcium carbonate in the sample.
Explanation:
Suppose in 100 g of sample of impure calcium carbonate
Percentage of calcium in the sample = 11%
Mass of the calcium in the sample = 11% of 100 g = [tex]\frac{11}{100}\times 100g=11 g[/tex]
Moles of calcium = [tex]\frac{11 g}{40 g/mol}=0.275 mol[/tex]
In 1 mole of calcium carbonate there are 1 mol of calcium .Then in 0.275 moles of calcium will be in :
[tex]\frac{1}{1}\times 0.275 mol=0.275 mol[/tex] calcium carbonate
Mass of 0.275 moles of calcium carbonate :
0.275 mol × 102 g/mol =28.05 g
Percentage of calcium carbonate in the sample:
[tex]\frac{28.05 g}{100 g}\times 100=28.05\%[/tex]
28.05% is the mass percent of calcium carbonate in the sample.
