The basketball boosters are selling school t-shirts for 20 dollars and pants for 45 dollars. Last week they sold 100 items and collected 2600 in sales. How much of each item did he sell?

Respuesta :

He sold 76 shirts and 24 pants.

Step-by-step explanation:

Given,

Cost of one t-shirt = $20

Cost of one pants = $45

Total items sold = 100

Total sales = 2600

Let,

x be the number of t-shirts

y be the number of pants

According to given statement;

x+y=100    Eqn 1

20x+45y=2600   Eqn 2

Multiplying Eqn 1 by 20

[tex]20(x+y=100)\\20x+20y=2000\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 3 from Eqn 2

[tex](20x+45y)-(20x+20y)=2600-2000\\20x+45y-20x-20y=600\\25y=600[/tex]

Dividing both sides by 25

[tex]\frac{25y}{25}=\frac{600}{25}\\y=24[/tex]

Putting in Eqn 1

[tex]x+24=100\\x=100-24\\x=76[/tex]

He sold 76 shirts and 24 pants.

Keywords: linear equations, subtraction

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