Respuesta :

nkirotedoreen46

Answer:

= 1.12 L

Explanation:

We are given;

  • Moles of neon at STP is 0.05 mol

We are required to calculate the volume;

  • According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP.
  • That is, 1 mole of a gas = 2.4 L

Therefore;

1 mole of Neon gas = 22.4 L

Thus;

Volume = Moles of the gas × molar gas volume

             = 0.05 mol × 22.4 L/mol

             = 1.12 L

Thus, the volume of neon gas at STP is 1.12 L

The volume of the 0.05 mol of neon gas at STP is 1.12 L. The volume can be calculated by the multiplying the moles of gas with molar gas volume.

How to calculate volume at STP?

The volume can be calculated by the multiplying the moles of gas with molar gas volume,

[tex]V = n \times V_m[/tex]

Where,

[tex]V[/tex] - volume

[tex]n[/tex] =- number of moles

[tex]V_m[/tex] - molar gas volume at STP

Put the values in the formula,

V = 0.05 mol × 22.4 L/mol

V = 1.12 L

Therefore, the volume of the 0.05 mol of neon gas at STP is 1.12 L.

Learn more about STP:

https://brainly.com/question/12083036

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