A clock mechanism at rest has a period of exactly 1 second. When this clock is observed while moving with a speed of 0.79 c, what is its period?

Respuesta :

Answer:

1.63103 seconds

Explanation:

[tex]\Delta t[/tex] = Actual period of clock = 1 second

v = Speed at which the observer is moving = 0.79 c

c = Speed of light = [tex]3\times 10^8\ m/s[/tex]

Time dilation is given by

[tex]\Delta t'=\frac{\Delta t}{\sqrt{1-\frac{v^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{1}{\sqrt{1-\frac{0.79^2c^2}{c^2}}}\\\Rightarrow \Delta t'=1.63103\ s[/tex]

The period is 1.63103 seconds