Answer:
1,298 °C was the temperature of the furnace.
Explanation:
Heat lost by platinum will be equal to heat gained by the water
[tex]-Q_1=Q_2[/tex]
Mass of platinum = [tex]m_1=100 g[/tex]
Specific heat capacity of platinum= [tex]c_1=130 J/kg^oC =0.130 J/g^oC[/tex]
Initial temperature of the iron = [tex]T_1=?[/tex]
Final temperature = [tex]T_2[/tex]=T = 10°C
[tex]Q_1=m_1c_1\times (T-T_1)[/tex]
Mass of water= [tex]m_2= 400 g[/tex]
Specific heat capacity of water= [tex]c_2=4.186 J/g^oC [/tex]
Initial temperature of the water = [tex]T_3=0^oC[/tex]
Final temperature of water = [tex]T_2[/tex]=T = 10°C
[tex]Q_2=m_2c_2\times (T-T_3)[/tex]
[tex]-Q_1=Q_2[/tex]
[tex]-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)[/tex]
On substituting all values:
[tex]-(100 g\times 0.130 J/g^oC\times (10^oC-T_1))=400\times 4.186\times (10^oC-0^oC)[/tex]
we get, [tex]T_1[/tex] = 1,298°C
1,298 °C was the temperature of the furnace.
