Respuesta :
Answer:
Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.
Explanation:
[tex]Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V[/tex]
[tex]Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V[/tex]
The substance having highest positive reduction [tex]E^o[/tex] potential will always get reduced and will undergo reduction reaction.
Reduction : cathode
[tex]Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V[/tex]..[1]
Oxidation: anode
[tex]Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V[/tex]..[2]
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the [tex]E^o_{cell}[/tex] of the reaction, we use the equation:
[tex]E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}[/tex]
[tex]E^o_{cell}=-0.036V-(-2.37 V)=2.334 V[/tex]
The overall reaction will be:
2 × [1] + 3 × [2] :
[tex]2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-[/tex]
Electrons on both sides will get cancelled :
[tex]2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)[/tex]
Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.
