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A heavy flywheel rotating on its central axis is slowing down because of friction in its bearings. At the end of the first minute of slowing, its rotational speed is 0.90 of its initial rotational speed of 325 rev/min. Assuming a constant rotational acceleration, find its rotational speed at the end of the second minute.

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Answer:

[tex]v_f=263.25\frac{rev}{min}[/tex]

Explanation:

Since we have a constant rotational acceleration, this means that every minute the initial rotational speed is reduced by a factor of 0.90. Therefore, after two minutes it will be given by:

[tex]v_f=0.90*0.90*v_0\\v_f=0.90*0.90*325\frac{rev}{min}\\v_f=263.25\frac{rev}{min}[/tex]

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