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Hippocrates magazine states that 35 percent of all Americans take multiple vitamins regularly. Suppose a researcher surveyed 750 people to test this claim and found that 296 did regularly take a multiple vitamin. Is this sufficient evidence to conclude that the actual percentage is different from 35% at the 5% significance level?
Select the [p-value, Decision to Reject (RH0) or Failure to Reject (FRH0)].

a) [p-value = 0.060, FRH0]

b) [p-value = 0.010, FRH0]

c) [p-value = 0.010, RH0]

d) [p-value = 0.005, RH0]

e) [p-value = 0.005, FRH0

Respuesta :

Answer:

p value = 0.005 for right tailed

Reject H0

Step-by-step explanation:

Given that Hippocrates magazine states that 35 percent of all Americans take multiple vitamins regularly.

Persons surveyed = 750

Of those survived no of persons who took multiple vitamin = 296

Sample proportion = p =0.395

q =1-p = 0.605

[tex]H_0:  p=0.35\\H_a:  p\neq 0.35[/tex]

(Two tailed test)

Assuming H0 is true standard error = [tex]\sqrt{0.35*0.65/750} \\=0.0174[/tex]

p difference = 0.045

Test statistic = [tex]\frac{0.045}{0.0174} \\=2.58[/tex]

p value = 0.005 for right tailed

Reject H0

Option d is right

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