Marika solved the equation (6x + 15)2 + 24 = 0. Her work is below. 1. (6x + 15)2 = –24 2. StartRoot (6 + 15) squared EndRoot = StartRoot negative 24 EndRoot 3. 6x + 15 = Negative 2 StartRoot 6 EndRoot 4. 6x = Negative 2 StartRoot 6 EndRoot – 15 5. x = StartFraction negative 2 StartRoot 6 EndRoot minus 15 Over 6 EndFraction Analyze Marika’s steps. Which statement is true about her work? In step 2, Marika should have simplified StartRoot negative 24 EndRoot to be 4 StartRoot negative 6 EndRoot. There are no real solutions to this equation because the square root of a negative number is not a real number. There should be two real solutions to this equation because StartRoot negative 24 EndRoot = Plus or minus 2 StartRoot 6 EndRoot. Marika correctly solved this equation.

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sparkyjones02 sparkyjones02 · Answer 1 · 2019-12-10T03:23:57+01:00

Answer:

There are no real solutions to this equation because the square root of a negative number is not real. So answer B

Step-by-step explanation:

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MrRoyal MrRoyal · Answer 2 · 2022-04-13T10:43:31+02:00

The true statement is that there are no real solutions to this equation because the square root of a negative number is not a real number

Equation solutions are the true values of x in the equation

The equation is given as:

(6x + 15)^2 + 24 = 0

Subtract 24 from both sides

(6x + 15)^2 = -24

Take the square root of both sides

6x + 15 = [tex]\sqrt{-24)[/tex]

The square root of -24 are complex numbers.

Hence, there are no real solutions to this equation because the square root of a negative number is not a real number

Read more about quadratic equations at:

https://brainly.com/question/8649555