Respuesta :
Answer:
0.01506, 6.06667,3.9334
Step-by-step explanation:
Given that you have 64 independent random variables all with an exponential distribution with mean 5 and variance 25 .
Let X denote the sample mean of the 64 random variables.
The sample mean i.e. X will have a normal distribution irrespective of the original parent distribution.
This is because of central limit theorem. The central limit theorem says that for large sample sizes randomly drawn, the sample mean would follow a normal distribution irrespective of the distribution of the population
X is N(5, [tex]\frac{\sigma}{\sqrt{n} } =\frac{5}{8} \\=0.6333[/tex]
a) X is N(5, 0.8333)
b) [tex]P(X>6) = 1-0.88494\\=0.01506\\[/tex]
c) 90th percentile of X = [tex]5+1.28*0.8333\\\\=6.06667[/tex]
d) 10th percentile = [tex]5-1.28*0.8333\\\\=3.9334[/tex]
