Answer:
The value of p=-20 makes the equation true
Step-by-step explanation:
we have
[tex]\frac{3}{5}p+\frac{1}{5}(40-p)=0[/tex]
Solve for p
Multiply by 5 both sides to remove the fraction
[tex]3p+(40-p)=0[/tex]
Combine like terns left side
[tex]2p+40=0[/tex]
subtract 40 both sides
[tex]2p+40-40=0-40[/tex]
[tex]2p=-40[/tex]
Divide by 2 both sides
[tex]p=-20[/tex]
therefore
The value of p=-20 makes the equation true
