What is the equation of the graphed line written in standard form?

A)2x + 3y = –6
B)2x + 3y = 6
C)y equals negative StartFraction 2 Over 3 EndFraction x minus 2.
D)y equals StartFraction 2 Over 3 EndFraction x minus 2.

What is the equation of the graphed line written in standard form A2x 3y 6 B2x 3y 6 Cy equals negative StartFraction 2 Over 3 EndFraction x minus 2 Dy equals St class=

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Answer:

Option A) 2x + 3y = –6

Step-by-step explanation:

step 1

Find the slope of the line

The formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

we have the points

(0,-2) ---> y-intercept

(-3,0) ---> x-intercept

substitute in the formula

[tex]m=\frac{0+2}{-3-0}[/tex]

[tex]m=\frac{2}{-3}[/tex]

[tex]m=-\frac{2}{3}[/tex]

step 2

Find the equation of the line in slope intercept form

[tex]y=mx+b[/tex]

where

m is the slope

b is the y-intercept

we have

[tex]m=-\frac{2}{3}[/tex]

[tex]b=-2[/tex]

substitute

[tex]y=-\frac{2}{3}x-2[/tex]

step 3

Convert to standard form

The equation of the line in standard form is equal to

[tex]Ax+By=C[/tex]

where

A is a positive integer

B and C are integers

we have

[tex]y=-\frac{2}{3}x-2[/tex]

Multiply by 3 both sides to remove the fraction

[tex]3y=-2x-6[/tex]

Adds 2x both sides

[tex]2x+3y=-6[/tex] ----> equation in standard form

Answer:

A

Step-by-step explanation:

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