Respuesta :
We want to find the components of a given force.
the answers are:
x-component = 3.99N
y-component = 3.01N
The force is of 5N and makes a 37° angle with the x-axis.
Then the components are just the legs of a right triangle with an hypotenuse of 5N.
x-component = 5N*cos(37°) = 3.99N
y-component = 5N*sin(37°) = 3.01N
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The horizontal component of pulling force is 3.99 N.
The vertical component of pulling force is 3.00 N.
Given data:
The magnitude of pulling force is, F = 5 N.
The angle of inclination is, [tex]\theta = 37^{\circ}[/tex].
The x-component of force is the horizontal component. And the expression for the horizontal component is,
[tex]F_{x}=Fcos\theta\\F_{x}=5 \times cos37\\F_{x}=3.99 \;\rm N[/tex]
Thus, the horizontal component of pulling force is 3.99 N.
The y-component of force is the vertical component. And the expression for the vertical component is,
[tex]F_{y}=Fsin\theta\\F_{y}=5 \times sin37\\F_{y}=3.00 \;\rm N[/tex]
Thus, the vertical component of pulling force is 3.00 N.
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