Respuesta :
Answer:
The system of equation that represent this situations are;
[tex]\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.[/tex]
Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.
Step-by-step explanation:
Let number of hat Chevy makes be h.
Also Let number of scarves Chevy makes be s.
Given:
Total Amount of yarns = 2 kg
Total number of items = 15
Since Items need to make are hat and scarves.
Hence the equation can be represented as;
[tex]h+s=15 \ \ \ \ equation \ 1[/tex]
Again Given:
Each hat uses 0.2 kilograms of yarn.
each scarf uses 0.1 kilograms of yarn.
Hence the equation can be represented as;
[tex]0.2h+0.1s=2 \ \ \ \ \ equation \ 2[/tex]
Hence the system of equation that represent this situations are;
[tex]\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.[/tex]
Now Solving these to find number of hats and number of scarves.
Multiplying equation 2 with 10 we get;
[tex]10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3[/tex]
Now Subtracting equation 1 from equation 3 we get;
[tex](2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5[/tex]
Now Substituting the value of h in equation 1 we get;
[tex]h+s= 15\\5+s =15\\s=15-5\\s=10[/tex]
Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.
Answer:
[tex]0.2h+0.1s=2\\h+s=15[/tex]
Step-by-step explanation:
This is based off the way khan said it was right when I had this problem
