12.5 mL of NaOH solution
Explanation:
We have the following chemical reaction in which sodium hydroxide (NaOH) react with acetic acid (CH₃-COOH) to form sodium acetate (CH₃-COONa) and water (H₂O):
NaOH + CH₃-COOH → CH₃-COONa + H₂O
molar concentration = number of moles / volume
number of moles = molar concentration × volume
number of moles of CH₃-COOH = 0.2 × 12.5 = 2.5 mmoles
*typically a vinegar solution have a concentration of acetic acid of 12.5 mol/L.
Taking in account the chemical reaction, we devise the following reasoning:
if 1 mmole of NaOH reacts with 1 mmole of CH₃-COOH
then X = 2.5 mmoles of NaOH reacts with 2.5 mmoles of CH₃-COOH
volume = number of moles / molar concentration
volume of NaOH solution = 2.5 / 0.2 = 12.5 mL
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molar concentration
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