Answer:
Impulse is [tex]6.3*10^{-9}\:N \cdot s[/tex]
The average force is [tex]6.3*10^{-6} N[/tex]
Explanation:
When a mass [tex]m[/tex] undergoes a change in velocity [tex]\Delta v[/tex], its impulse [tex]I[/tex] is
[tex]I =m\Delta v[/tex]
and if a force [tex]F[/tex] is acting for time [tex]t[/tex], then the impulse [tex]I[/tex] is given by
[tex]I=F*t[/tex]
Now the mass of the spores in kg is
[tex]m=1.4*10^{-6}g*\frac{10^{-3}kg}{g}=1.4*10^{-9}kg[/tex]
we calculate the impulse from the first formula:
[tex]I =m\Delta v =(1.4*10^{-9}kg)(4.5\frac{m}{s} )=6.3*10^{-9}N\cdot s[/tex]
[tex]\boxed{I=6.3*10^{-9}\:N \cdot s}[/tex]
Now that we have impulse, we calculate the average force on the spore from the second formula:
[tex]F=\frac{I}{t} =\frac{6.3*10^{-9}}{1*10^{-3}s}=6.3*10^{-6} N[/tex]
[tex]\boxed{F=6.3*10^{-6} N}[/tex]
The average force on a spore is mathematically given as
F=6.3*10^{-6}N
Generally the equation for the impulse is mathematically given as
I=ft
Where
m=1.4e{-9}
Therefore
I=ft
I =mdv
[tex]I=(1.4*10^{-9})(4.5\frac{m}{s} )\\\\I=6.3*10^{-9}Ns[/tex]
The average force is
[tex]F=\frac{I}{t}\\\\F=6.3*10^{-9}/1e{-3}[/tex]
F=6.3*10^{-6}N
For more information on Force
https://brainly.com/question/26115859
