Answer : The nutritional Calories present per gram of the candy are 5.48 cal/g.
Explanation :
First we have to calculate the heat given off by the combustion of this candy.
[tex]q=c\times \Delta T[/tex]
where,
q = heat released by the reaction = ?
c = specific heat of calorimeter = [tex]29.60kJ/K[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex]2.79^oC=2.79K[/tex] (Change in kelvin temperature = Change in Celsius temperature)
Now put all the given values in the above formula, we get:
[tex]q=(29.60kJ/K)\times (2.79K)[/tex]
[tex]q=82.58kJ[/tex]
Now we have to convert heat from kJ to cal.
Conversion used : 1 cal = 4.186 kJ
As, 4.186 kJ heat = 1 cal
So, 84.58 kJ heat = [tex]\frac{82.58kJ}{4.186kJ}\times 1cal=19.73cal[/tex]
Now we have to calculate the nutritional Calories are there per gram of the candy.
Amount of nutritional Calories = [tex]\frac{19.73cal}{3.60g}=5.48cal/g[/tex]
Therefore, the nutritional Calories present per gram of the candy are 5.48 cal/g.
