A person listening to a siren from a stationary police car observes the frequency and wavelength of that sound. The car now drives rapidly away from the person.
O The wavelength of the sound the person observes will be shorter than it was, but the frequency will not be changed.
O The frequency of the sound the person observes will be higher than it was, but the wavelength will not be changed.
O The wavelength of the sound the person observes will be longer than it was, and the frequency will also be lower than it was.
O The wavelength of the sound the person observes will be shorter than it was, and the frequency will also be higher than it was.

Respuesta :

Answer:

The wavelength of the sound the person observes will be longer than it was, and the frequency will also be lower than it was.

Explanation:

From Doppler effect we know that

[tex]f_L= f_0(\frac{V-V_s}{V+V_0})[/tex]

f_L= frequency observed by the listener

f_s= frequency of the source

v= velocity of sound

Vs= velocity of source

Vo=  velocity of observer

so

when the Source( car siren) moves away, Vs increases and the factor (V -Vs)(V +V_0) decreases

thus f_L also Decreases

option C it is