Answer:
Normal force on Frieda is 623.71N
Explanation:
Given that Frieda stands on a hill with a slope of 12°
Let mass of Frieda is m=65kg
θ is slope of hill = 12°
Figure show that free body diagram of Frieda standing on hill if slope 12°
From free body diagram,
Normal force = mgcosθ
= (65)(9.81)(cos12)
= (65)(9.81)(0.9781)
= 623.71N
Thus, normal force on Frieda is 623.71N
