The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration [tex]g=9.8 m/s^2[/tex] towards the ground. So we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
[tex]a=g=9.8 m/s^2[/tex] is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:
[tex]v=0+(9.8)(0.75)=7.35 m/s[/tex]
Learn more about free fall:
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