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A young hockey player stands at rest on the ice holding a 1.2-kg helmet. The player tosses the helmet directly in front of him with a speed of 7.0 m/s and recoils with a speed of 0.30 m/s .
Find the mass of the hockey player.

Respuesta :

Answer:

[tex]M_p = 28 kg[/tex]    

Explanation:

For answer this we will use the law of the conservation of the linear momentum P:

[tex]P_i = P_f[/tex]

so:

0 = [tex]M_cV_c + M_pV_p[/tex]

where [tex]M_c[/tex] is the mass of the helmet,  [tex]V_c[/tex] is the velocity of the helmet, [tex]M_p[/tex] is the mass of the hockey player and [tex]V_p[/tex] is the velocity of the hockey player after launch his helmet.

note: we will take the direction of the helmet like positive.

Replacing values, we get:

0 = [tex](1.2 kg)(7m/s) + M_p(-0.3m/s)[/tex]

Solving for [tex]M_p[/tex]:

[tex]M_p = 28 kg[/tex]

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