Answer:
V₂ = 6.14 L
Explanation:
Given data:
Initial volume = 9.5 L
Initial pressure = 1.02 atm
Initial temperature = 20.1 °C (20.1 +273 = 293.1 K)
Final temperature = 15°C (15+273 = 288 K)
Final volume = ?
Final pressure = 1.55 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 1.02 atm × 9.50 L × 288 K / 293.1 K × 1.55 atm
V₂ = 2790.72 atm. L.K / 454.305 K. atm
V₂ = 6.14 L
