Answer:
[tex]58.8\ mm^2[/tex]
Step-by-step explanation:
we know that
The area of the figure is equal to the area of rectangle plus the area of semicircle
step 1
Find the area of rectangle
The area of rectangle is equal to
[tex]A=bh[/tex]
where
[tex]b=9\ mm\\h=3\ mm[/tex]
substitute
[tex]A=(9)(3)=27\ mm^2[/tex]
step 2
Find the area of semicircle
The area of semicircle is equal to
[tex]A=\frac{1}{2}\pi r^{2}[/tex]
we have
[tex]r=9/2=4.5\ mm[/tex] ---> the radius is half the diameter
[tex]\pi =3.14[/tex]
substitute
[tex]A=\frac{1}{2}(3.14) (4.5)^{2}[/tex]
[tex]A=31.8\ mm^2[/tex]
step 3
Find the area of the figure
[tex]A=27+31.8=58.8\ mm^2[/tex]